Quarter-Wave Resonance

acoustics resonance formants vocal-tract
Last updated: 2025-01-19

Quarter-Wave Resonance

Resonance in a tube is the constructive interference of waves experiencing multiple reflections. It is the essence of vocal tract acoustics. The human vocal tract, like the tube of a wind or brass instrument, resonates at certain special frequencies produced by the sound source. These frequencies depend on the shape of the vocal tract and determine many speech sounds (phonemes) from which syllables and words are made.

The Quarter-Wave Tube Configuration

Quarter-wave resonance tube diagram Figure 6.3: Resonance in an open-closed (quarter-wave) tube. A reflection diagram is shown to the right, and source frequencies for resonance are shown underneath.

Consider a tube of length L, closed at one end and open at the other. This tube is called a quarter-wave resonator for reasons that will become evident. The tube is shown in a vertical position, with the open end on top. A small hole at the bottom makes the “closed end” not quite closed, but approximately so.

This hole, which is used to supply acoustic energy to the tube, is a representation of the glottis in the human airway. It could also represent the gap between a brass player’s lips. For any vibrating source, this hole (or slit) will open and close periodically according to the criteria of oscillation described in Chapter 4.

Space-Time Reflection Diagram

A wave reflection diagram is shown to the right of the tube. Time is on the horizontal axis, and space is on the vertical axis. Instead of “freezing” one variable and showing pressure versus either space or time, we have essentially created a three-dimensional representation by showing both space and time and letting the magnitude of a pressure peak be the length of an arrow. Polarity of the wavefront is also indicated at the side of the arrow.

Wave Propagation Sequence

Assume that a sinusoidal flow is introduced through the hole. This can be any frequency component of a complex source waveform. The initial peak of the sinusoids is chosen with a plus sign (for the sake of discussion), indicating that the polarity of the initial pressure disturbance at the hole is a compression.

The sequence of events is:

  1. Upward propagation: The positive pressure disturbance propagates the length of the tube toward the open end
  2. First reflection (r < 0): At the open end (expansion to infinite area), the compression inverts to create a rarefaction of nearly the same magnitude
  3. Downward propagation: The rarefaction travels back down the tube
  4. Second reflection (r > 0): At the bottom (nearly closed), the rarefaction reflects with the same polarity, remaining a rarefaction
  5. Second upward trip: The rarefaction travels to the top and inverts again to become a compression
  6. Cycle completion: After the second round trip, the pressure pattern is identical to the initial one

Standing Wave Formation

A standing wave is created in this process. Note that:

  • The pressure magnitude is always doubled at the bottom (either doubly positive or doubly negative as the alternating plus and minus signs indicate)
  • The pressure magnitude always remains near zero at the top (because incident and reflected waves tend to cancel each other)

This standing wave would persist indefinitely in the tube, even for a single pressure disturbance introduced at the hole, were it not for the fact that some energy is lost in propagation and reflection. The small amount of acoustic energy leaving at the top of the tube and at the bottom hole attenuates the reflected waves.

Resonance Condition

The standing-wave pattern can be reinforced by periodic source inputs, provided the period T of the injected flows has a simple relationship to the transit time of the wave. If we define t₀ to be the transit time for one round trip of the wave, resonance occurs when:

t₀ = T/2
or  t₀ = 3T/2
or  t₀ = 5T/2
or  t₀ = nT/2  (where n is any positive odd integer)

The transit time may be expressed as the total distance (two tube lengths) divided by the speed of sound c:

t₀ = 2L/c

For resonance, then:

2L/c = nT/2

where n is any positive odd integer. Because the period T is the inverse of the frequency F of the source, this can be rewritten as:

F = n(c/4L)

Formant Frequencies

At this point we introduce the term formant, which will be used extensively throughout the text. A formant is a resonance of the vocal tract. The equation above identifies the formant frequencies of a closed-open uniform tube.

There is an infinite number of such formant frequencies, but only a few are usually of interest. In analogy with the normal modes of vibration of vocal fold tissue, formants are the normal modes of the vocal tract air column.

Notation

To distinguish between each of the formant frequencies, it is customary to place a subscript n on the symbol F so that Fₙ represents the entire collection of formant frequencies (n = 1, 2, 3, 4 … ∞). Only the odd integers apply, however. To select these odd integers automatically, the formant frequencies can be rewritten as:

Fₙ = (2n - 1)(c/4L)

where n can now be any positive integer. The beauty of this notation is that the subscript on the frequency (left side) corresponds to the value of n chosen on the right. For n = 1, 2, …, we get F₁ = c/4L, F₂ = 3c/4L, and so on.

Why “Quarter-Wave”?

It is now possible to understand why the open-closed tube is called a quarter-wave resonator. Recalling that F = c/λ for any wave, where λ is the wavelength, it is apparent that λ = 4L when n = 1. In other words, for the lowest formant the wavelength is four times the length of the tube. Stated another way, the tube length is a quarter of a wavelength long at its first formant frequency.

Standing Wave Patterns

Standing wave pressure patterns Figure 6.4: Pressure distribution (shown by stipple density and line drawings) in the closed-open resonance tube: (a) the lowest quarter-wave resonance, (b) three-quarter wave resonance, and (c) five-quarter wave resonance.

The pressure patterns for the first three formants show:

  • First formant (n = 1): λ/4 pattern - pressure decreases from maximum at closed end to zero at open end
  • Second formant (n = 2): 3λ/4 pattern - tube length corresponds to three-quarters of a wavelength
  • Third formant (n = 3): 5λ/4 pattern - tube length corresponds to five-quarters of a wavelength

Note that pressure doubling (positive or negative) occurs at several locations along the tube as n increases, but always at the closed end and never at the open end.

These are “snapshots” in time. A half period later, all of the compressions (+) become rarefactions (-), and vice versa. The important feature of a standing wave is that the amplitudes of the acoustic pressures (the maximum positive or negative excursions) anywhere in space remain the same.

Numerical Example

For an average male vocal tract length of 17.5 cm and a sound velocity of 35,000 cm/s, the formant frequencies are:

Fₙ = (2n - 1) × 35,000/(4 × 17.5) = (2n - 1) × 500 Hz

The lowest four formant frequencies are:

  • F₁ = 500 Hz
  • F₂ = 1,500 Hz
  • F₃ = 2,500 Hz
  • F₄ = 3,500 Hz

These formants are evenly spaced at 1,000 Hz intervals for a uniform tube.

Summary

The quarter-wave resonator is fundamental to understanding vocal tract acoustics. A tube closed at one end (the glottis) and open at the other (the lips) resonates at frequencies given by Fₙ = (2n-1)(c/4L), where only odd multiples of the fundamental are present. These resonances, called formants, are created by constructive interference of waves reflecting between the two ends.

The tube is called “quarter-wave” because at the lowest formant frequency, the tube length equals one-quarter of the wavelength. Standing wave patterns show pressure maxima at the closed end and pressure minima at the open end, with the complexity of the pattern increasing for higher formants.


Key Takeaways

  • ✅ Quarter-wave resonators are closed at one end and open at the other, like the vocal tract
  • ✅ Formant frequencies are given by Fₙ = (2n-1)(c/4L), containing only odd harmonics
  • ✅ Standing waves form through constructive interference of multiply-reflected waves
  • ✅ Pressure is always maximum (doubled) at the closed end and minimum (zero) at the open end
  • ✅ For a 17.5 cm vocal tract, formants are spaced at approximately 1000 Hz intervals
  • ✅ The term “quarter-wave” refers to the tube length being λ/4 at the first formant

Further Reading

  1. Fant, G. (1960). Acoustic theory of speech production. The Hague: Mouton.
  2. Titze, I. R. (2000). Principles of voice production (2nd ed.). National Center for Voice and Speech.
  3. Stevens, K. N. (1998). Acoustic phonetics. MIT Press.

Connections across chapters

Practice all connections

Each prompt ties this topic to another chapter. Predict the outcome before you open the model answer.

Ch. 6 · Quarter-Wave Resonance (this page) Ch. 10 · Hypothesis One: Subglottal Resonances

The trachea as a resonator and the passaggio

Treat the trachea as a tube about 15 cm long, effectively closed at the glottis. Calculate its first resonance with c = 350 m/s, then use the subglottal resonance hypothesis to predict the fundamental frequencies at which the third and fourth harmonics would meet that resonance, and say what is claimed to happen there.

Think it through, then show a model answer

A quarter-wave tube resonates at f₁ = c/4L = 350/(4×0.15) ≈ 580 Hz; allowing for the lungs' loading, the first subglottal formant is usually put near 500–600 Hz (the chapter uses about 510 Hz). The third harmonic meets it when F₀ ≈ 170 Hz and the fourth when F₀ ≈ 130–150 Hz, and the chapter's interference analysis also singles out F₀ near 300 Hz and near 510 Hz. The hypothesis is that when a harmonic sits at the subglottal resonance the tracheal air column pushes back on the folds with a phase that can either steady or disrupt vibration; the unfavourable case destabilises the cycle and triggers an involuntary register shift, matching the primo passaggio around 300–350 Hz. Because training moves the passaggio, this cannot be the whole story.

A good answer mentions

  • Quarter-wave resonance of a 15 cm trachea is near 580 Hz; the first subglottal formant is taken as about 510 Hz
  • Harmonic–resonance coincidences predict F₀ values in the passaggio region
  • Phase-dependent loading from the trachea can destabilise vibration; training limits the hypothesis

Ch. 5 · Wavelength Ch. 6 · Quarter-Wave Resonance (this page)

Why formants, not the fundamental, set up standing waves

A man phonates at F₀ = 125 Hz through a 17.5 cm vocal tract in which sound travels at about 350 m/s. Calculate the wavelength of the fundamental and the first three resonances of the tract treated as a quarter-wave tube. Then explain why the fundamental itself does not "resonate" while its harmonics near 500, 1500 and 2500 Hz do.

Think it through, then show a model answer

Wavelength is c/F₀ = 350/125 = 2.8 m, sixteen times the length of the tract, so along the tract the pressure of the fundamental is almost uniform and no standing wave can form. The tract, closed at the glottis and open at the lips, resonates when its length is an odd number of quarter wavelengths: Fₙ = (2n−1)c/4L = 500, 1500 and 2500 Hz, with wavelengths of 70, 23 and 14 cm that are comparable to the tract. The voice source supplies harmonics at every multiple of 125 Hz, and it is the harmonics that fall near 500, 1500 and 2500 Hz (the 4th, 12th and 20th) that are reinforced by the formants; the fundamental is simply too long a wave to be shaped by a tube this short.

A good answer mentions

  • λ = c/F₀ gives 2.8 m for the fundamental, far longer than the tract
  • Quarter-wave resonances: Fₙ = (2n−1)c/4L ≈ 500, 1500, 2500 Hz
  • Resonance requires wavelengths comparable to the tube, so harmonics rather than F₀ are amplified

Ch. 5 · Propagation Velocity Ch. 6 · Quarter-Wave Resonance (this page)

Helium raises the formants but not the pitch

A speaker inhales helium and talks. Predict which of these change and by how much: the fundamental frequency, the formant frequencies and the perceived quality. Explain each prediction from the physics of propagation velocity and tube resonance.

Think it through, then show a model answer

The fundamental is set by the vocal folds, whose mass and stiffness are unchanged, so F₀ stays essentially the same. Sound travels about 2.5 times faster in helium than in air because helium is much less dense (c = √(K/ρ)), and the quarter-wave resonances Fₙ = (2n−1)c/4L scale directly with c, so every formant moves up by roughly the same factor (in practice a helium–air mixture gives a smaller shift). The listener hears the same pitch with a much brighter, "squeaky" timbre because the spectral envelope has been pushed up while the harmonic spacing has not.

A good answer mentions

  • F₀ is a tissue property, so it does not change
  • Propagation velocity rises in the less dense gas, and resonances scale with c
  • All formants rise by the same factor, giving the bright, squeaky quality